Minggu, 11 Maret 2012

Creating Form Insert Data

php mysql basic step by step tutorial In order to make this input data is 'user friendly', you can make a HTML form for input data, example: 

01<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01
02Transitional//EN"
03"http://www.w3.org/TR/html4/loose.dtd">
04<html>
05 
06<head>
07<title>Form Input Data</title>
08</head>
09 
10<body>
11<table border="1">
12  <tr>
13    <td align="center">Form Input Employees Data</td>
14  </tr>
15  <tr>
16    <td>
17      <table>
18        <form method="post" action="input.php">
19        <tr>
20          <td>Name</td>
21          <td><input type="text" name="name" size="20">
22          </td>
23        </tr>
24        <tr>
25          <td>Address</td>
26          <td><input type="text" name="address" size="40">
27          </td>
28        </tr>
29        <tr>
30          <td></td>
31          <td align="right"><input type="submit"
32          name="submit" value="Sent"></td>
33        </tr>
34        </table>
35      </td>
36    </tr>
37</table>
38</body>
39</html>

The result:





This HTML form will send two variable, $name and $address variable, into input.php file as describe in the ACTION parameter of FORM HTML.


01<?
02//the example of inserting data with variable from HTML form
03//input.php
04mysql_connect("localhost","root","admin");//database connection
05mysql_select_db("employees");
06 
07//inserting data order
08$order = "INSERT INTO data_employees
09            (name, address)
10            VALUES
11            ('$name',
12            '$address')";
13 
14//declare in the order variable
15$result = mysql_query($order);  //order executes
16if($result){
17    echo("<br>Input data is succeed");
18} else{
19    echo("<br>Input data is fail");
20}
21?>

  
After you have already made input.php, fill the input data and then click the sent button such as:




For the result:
As for the exercises, put some of datas into employees database.    

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